Steps to display images in the grid view control:
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Create a table schema in the following format in Sql Server
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Design the web form with the following controls
Textbox, Fileupload control, Button, Gridview, Sqldatasource
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Create the sqldatasource connectionstring with the datasource property and set the datakey name to ID
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Add a Generic handler to the application(In the solution explorer right click and add select generic handler from the Templates in the New Item
It consists the code of Selecting the records from the table and displaying them in the gridview
Handler code:
<%@ WebHandler Language="C#" Class="Handler" %>
using System;
using System.Web;
using System.Configuration;
using System.Data.SqlClient;
public class Handler : IHttpHandler {
public void ProcessRequest (HttpContext context)
{
SqlConnection con = new SqlConnection();
con.ConnectionString = ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString;
// Create SQL Command
SqlCommand cmd = new SqlCommand();
cmd.CommandText = "Select ImageName,Image from Images where ID =@ID";
cmd.CommandType = System.Data.CommandType.Text;
cmd.Connection = con;
SqlParameter ImageID = new SqlParameter("@ID", System.Data.SqlDbType.Int);
ImageID.Value = context.Request.QueryString["ID"];
cmd.Parameters.Add(ImageID);
con.Open();
SqlDataReader dReader = cmd.ExecuteReader();
dReader.Read();
context.Response.BinaryWrite((byte[])dReader["Image"]);
dReader.Close();
con.Close();
}
public bool IsReusable
{
get
{
return false;
}
}
}