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Calculate natural numbers that are divide by 7 & 8 using Java
Senthilvelan Sambamoorthy
Aug 13
2016
Code
591
0
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ssvnat.rar
//NATURALS NUMBERS THAT ARE DIVISIBLE BY 7 & 8
import
java.io.*;
class
ssvnat
{
public
static
void
main(String arg[])
throws
IOException
{
int
i,a,b,s=
0
,start,end;
BufferedReader br=
new
BufferedReader(
new
InputStreamReader(System.in));
System.out.println(
"\n\t\t*** NATURALS NUMBERS THAT ARE DIVISIBLE BY 7 & 8 *** \n"
);
System.out.print(
"Enter the number will be started : "
);
start=Integer.parseInt(br.readLine());
System.out.print(
"Enter the number to be end : "
);
end=Integer.parseInt(br.readLine());
for
(i=start;i<=end;i++)
{
a=i%
7
;
b=i%
8
;
if
((a==
0
)&&(b==
0
))
{
System.out.print(
"\t"
+ i);
s=s+i;
}
}
System.out.print(
"\n\nThe Sum of Numbers that are divisible by 7 and 8 : "
+ s);
System.out.println();
}
}
Java