Program for Reverse a Number in C#

This blog show how to print reverse a number in C# language.

Write a program where user gives two inputs digit, the program reverse the inputs and add them and again reverse there sum.

For Example:

Input:

Enter first number: 56
Enter second number:89

Output:

reverse of first number: 65
reverse of second number:98

sum of two reverse no is: 163

reverse of sum: 361

C# Code:

using System;
public class SumOfDigit
{
    public static void Main()
    {
        int number1, number2;
        int sum = 0;
        Console.Write("Enter the first Number: ");
        number1 = Convert.ToInt32(Console.ReadLine());
        Console.WriteLine("Reverse of first Number: {0}\n", ReverseNumber(number1));
        Console.Write("Enter the second Number: ");
        number2 = Convert.ToInt32(Console.ReadLine());
        Console.WriteLine("Reverse of second Number: {0}\n", ReverseNumber(number2));
        sum = ReverseNumber(number1) + ReverseNumber(number2);
        Console.WriteLine("\n\nSum of Two reverse number is: \t{0}", sum);
        sum = ReverseNumber((ReverseNumber(number1)) + (ReverseNumber(number2)));
        Console.WriteLine("Reverse of sum of Two number is: \t{0}", sum);
    }
    public static int ReverseNumber(int digit)
    {
        int x, reverse = 0;
        while (digit != 0)
        {
            x = digit % 10;
            reverse = reverse * 10 + x;
            digit = digit / 10;
        }
        return (reverse);
    }
}

Output


Fig: Screenshot of Output

Note: we can also optimize the code by adding a variable reverseSum and store the value of reverse of sum (Line-29) in it.