timer opens two windows instead of one

Inaam Hammouda

10y980Visual Basic .NET

i am using tow timers in my winForm

their Interval is 1000

when they stop (both for the same reason => if (v==0) show the new window ;timer1.stop ;timer 2.stop

but it opens two new windows , i just need one

any suggestions on how

thank you

7 Replies

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Ranjit Powar10y ago
Application.OpenForms is collection which contains all open forms in application. Here we check that form Arret618 is opened or not. If it is not found in OpenForms collection then we open it.

If your problem solved, then select correct answer.
0
Inaam Hammouda10y ago
thank you so much ,

but do you mind explain what you did , i never used that
0
Ranjit Powar10y ago
public void READDM2()
{
string dm_position = "3030";
UInt16 dmval = 0;
try
{
if (!plc1.ReadDM(Convert.ToUInt16(dm_position), ref dmval))
{
throw new Exception(plc1.LastError);
}
vitesseVal.Text = dmval.ToString();
if (vitesseVal.Text == "0")
{
    bool isOpen = false;
foreach (Form frm in Application.OpenForms)
{
if (frm.Name == "Arret618")
{
isOpen=true;
}
}
if(!isOPen)
{
   Arret618 ss = new Arret618();
   ss.Show();
}

timer2.Stop();
timer3.Stop();
}
}
catch (Exception ex)
{
MessageBox.Show(this, "ReadDM() Error: " + ex.Message);
}
0
Inaam Hammouda10y ago
timer1 call READM and timer 2 call READM1 ...

all i want when my program stop reading because the value is 0 it opens one frame instead of two
0
Ranjit Powar10y ago
In which event do you call method READDM2().
0
Inaam Hammouda10y ago
public void READDM2()
{
string dm_position = "3030";
UInt16 dmval = 0;
try
{
if (!plc1.ReadDM(Convert.ToUInt16(dm_position), ref dmval))
{
throw new Exception(plc1.LastError);
}
vitesseVal.Text = dmval.ToString();
if (vitesseVal.Text == "0")
{
Arret618 ss = new Arret618();
ss.Show();

timer2.Stop();
timer3.Stop();
}
}
catch (Exception ex)
{
MessageBox.Show(this, "ReadDM() Error: " + ex.Message);
}
0
Ranjit Powar10y ago
post your code
0