Sheikh parvaz

Sheikh parvaz

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Sending email to many in databes table

Aug 6 2014 2:21 AM
The below program show me 
 

A recipient must be specified.

Kindly help 
 
 
public partial class _Default : System.Web.UI.Page
{
DataSet ds = new DataSet();
SqlCommand cmd = new SqlCommand();
protected void Page_Load(object sender, EventArgs e)
{
}
protected void btnSendEmail_Click(object sender, EventArgs e)
{
if (txtemailfrom.Text == "" || txtsubject.Text == "" || txtbody.Text == "")
{
lblmail.Text = "Please fill all mandatory fields.";
lblmail.Visible = true;
return;
}
SmtpClient smtpClient = new SmtpClient();
MailMessage mailMessage = new MailMessage();
SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["stringconnect"].ConnectionString);
ArrayList list_emails = new ArrayList();
int i = 0;
string email;
con.Open();
SqlCommand cmd = new SqlCommand("Select EmailId from SendEmailToStudent", con);
SqlDataReader read_Email = cmd.ExecuteReader();
while (read_Email.Read())
{
email = read_Email.GetValue(i).ToString();
list_emails.Add(email); //Add email to a arraylist
i = i + 1 - 1;
}
read_Email.Close();
con.Close(); //Close connection
foreach (string email_to in list_emails)
{
if (fileAttachement.PostedFile != null)
{
HttpPostedFile AttachFile = fileAttachement.PostedFile;
int AttachFileLength = AttachFile.ContentLength;
if (AttachFileLength > 0)
{
// FileName = Path.GetFileName(fileAttachement.PostedFile.FileName);
}
}
MailAddress fromAddress = new MailAddress(txtemailfrom.Text);
mailMessage.From = fromAddress;
mailMessage.Subject = txtsubject.Text;
mailMessage.Body = txtbody.Text;
string Body = "";
Body += '\n' + "From:" + txtemailfrom.Text;
Body += '\n' + "";
Body += '\n' + "Subject:" + txtsubject.Text;
Body += '\n' + "";
Body += '\n' + txtbody.Text;
mailMessage.IsBodyHtml = true;
mailMessage.Body = Body;
SmtpClient smtp = new SmtpClient("SMTP Server");
smtpClient.Send(mailMessage);
lblmail.Visible = true;
lblmail.Text = "Your mail has been sent successfully";
tblemail.Visible = true;
}
txtemailfrom.Text = "";
txtsubject.Text = "";
txtbody.Text = "";
}
}

Answers (1)