Hello All, I want to break the string by using the Regular Expression: String:'(KEIN_HYBRID + (G011, G012) + !(111_HIGH_SECURITY) + Zylinderzahl Output: ( KEIN_HYBRID + (G011) + !(111_HIGH_SECURITY) + Zylinderzahl ) ( KEIN_HYBRID + (G012) + !(111_HIGH_SECURITY) + Zylinderzahl ) Thanks in Advance

This should do it: using System; using System.Text.RegularExpressions; class Test { static void Main() { string input = "(KEIN_HYBRID + (G011, G012) + !(111_HIGH_SECURITY) + Zylinderzahl string re = @"^($\w+\s*\+\s*)(\()(.*?)($)(.*)$"; Match m = Regex.Match(input, re); string str1 = m.Groups[1].Value; string str2 = m.Groups[2].Value; string[] split = Regex.Split(m.Groups[3].Value, @",\s*"); string str4 = m.Groups[4].Value; string str5 = m.Groups[5].Value; foreach(string s in split) { Console.WriteLine("{0}{1}{2}{3}{4}", str1, str2, s, str4, str5); } Console.ReadKey(); } }

Answer

Regular Expression as different

jithendra pasala

11y

936

Hello All,

I want to break the string by using the Regular Expression:

String:"(KEIN_HYBRID + (G011, G012) + !(111_HIGH_SECURITY) + Zylinderzahl<12)"

Output:

(KEIN_HYBRID + (G011) + !(111_HIGH_SECURITY) + Zylinderzahl<12)

(KEIN_HYBRID + (G012) + !(111_HIGH_SECURITY) + Zylinderzahl<12)

Thanks in Advance

Regular Expression as different

Answers (1)