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jithendra pasala
NA
53
37.1k
Regular Expression as different
Apr 29 2014 8:23 AM
Hello All,
I want to break the string by using the Regular Expression:
String:"(KEIN_HYBRID + (G011, G012) + !(111_HIGH_SECURITY) + Zylinderzahl<12)"
Output:
(
KEIN_HYBRID +
(G011) +
!(111_HIGH_SECURITY) + Zylinderzahl<12
)
(
KEIN_HYBRID +
(G012) +
!(111_HIGH_SECURITY) + Zylinderzahl<12
)
Thanks in Advance
Reply
Answers (
1
)
Regular Expression as ((G030, G031, G038) + (KEIN_HYBRID))
clase sockets