print the range between given numbers, input by user

Mngaro Mwazenje

Create the method public static void PrintNumbersInRange(List numbers, int lowerLimit, int upperLimit) in the exercise template. The method prints the numbers in the given list whose values are in the range [lowerLimit, upperLimit]. A few examples of using the method are supplied below.

List<int> numbers = new List<int>();
numbers.Add(3);
numbers.Add(2);
numbers.Add(6);
numbers.Add(-1);
numbers.Add(5);
numnbers.Add(1);
Console.WriteLine("The numbers in the range [0, 5]");
PrintNumbersInRange(numbers, 0, 5);

The numbers in the range [0, 5]

anyone??

7 Replies

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Guest User6y ago
Accepted answer
Show your new code.
0
Mngaro Mwazenje6y ago
1. using System;
2. using System.Collections.Generic;
3. using System.Linq;
5. namespace exercise_75
6. {
7. class Program
8. {
9. public static void PrintNumbersInRange(List<int> numbers, int lowerLimit, int upperLimit)
11. {
12. foreach (int number in numbers.Where (number => number >= lowerLimit && number <= upperLimit))
13. {
14. Console.WriteLine(number);
15. }
16. }
17. public static void Main(string[] args)
18. {
19. // Example method calls for testing your method.
20. List<int> numbers = new List<int>();
21. numbers.Add(3);
22. numbers.Add(2);
23. numbers.Add(6);
24. numbers.Add(-1);
25. numbers.Add(5);
26. numbers.Add(1);
28. Console.WriteLine("The numbers in the range [0, 5]");
29. PrintNumbersInRange(numbers, 0, 5);
30. }
31. }
32. }
this worked
0

Avnish Kumar6y ago

Try this one:

public static void Main(string[] args)
{
List<int> numbers = new List<int>();
numbers.Add(3);
numbers.Add(2);
numbers.Add(6);
numbers.Add(-1);
numbers.Add(5);
numbers.Add(1);
Console.WriteLine("The numbers in the range [0, 5]");
PrintNumbersInRange(numbers, 0, 5);
}
private static void PrintNumbersInRange(List<int> numbers, int v1, int v2)
{
numbers.Where(x => x >= v1 && x <= v2).ToList().ForEach(x => Console.WriteLine(x));
}

Please add System.Linq namespace for .Where() method.

Mngaro Mwazenje6y ago

System.Collections.Generic.List`1[System.Int32]

it displays the list type and not the contents

Guest User6y ago

Add:

using System.Linq;

Mngaro Mwazenje6y ago

foreach (int number in numbers.Where

i dont have the .where command from the dropdown list, i did it without and got this error!!

Program.cs(12,28): error CS0149: Method name expected

Guest User6y ago

Try this:

void Main()
{
List<int> numbers = new List<int>();
numbers.Add(3);
numbers.Add(2);
numbers.Add(6);
numbers.Add(-1);
numbers.Add(5);
numbers.Add(1);
Console.WriteLine("The numbers in the range [0, 5]");
PrintNumbersInRange(numbers, 0, 5);
}
public static void PrintNumbersInRange(List<int> numbers, int low, int high)
{
foreach (int number in numbers.Where(number => number >= low && number <= high))
{
Console.WriteLine(number);
}
}