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karthika pommudu
NA
321
34.6k
Pagination signout when click next page
Mar 30 2020 4:41 AM
Whenever I click the next page in pagination icon/button,its jumped to signout.
Please advice and help me to clear this.
$showRecordPerPage
= 5;
if
(isset(
$_GET
[
'page'
]) && !
empty
empty
(
$_GET
[
'page'
])){
$currentPage
=
$_GET
[
'page'
];
}
else
{
$currentPage
= 1;
}
$startFrom
= (
$currentPage
*
$showRecordPerPage
) -
$showRecordPerPage
;
$totalEmpSQL
=
"SELECT * FROM feedback where id !='' and name!='' "
;
$allEmpResult
= mysqli_query(
$link
,
$totalEmpSQL
);
$totalEmployee
= mysqli_num_rows(
$allEmpResult
);
$lastPage
=
ceil
(
$totalEmployee
/
$showRecordPerPage
);
$firstPage
= 1;
$nextPage
=
$currentPage
+ 1;
$previousPage
=
$currentPage
- 1;
html code:
---------------
<nav aria-label=
"Page navigation"
>
<ul
class
=
"pagination"
>
<?php
if
(
$currentPage
!=
$firstPage
) { ?>
<li
class
=
"page-item"
>
<a
class
=
"page-link"
href=
"?page=<?php echo $firstPage ?>"
tabindex=
"-1"
aria-label=
"Previous"
>
<span aria-hidden=
"true"
>First</span>
</a>
</li>
<?php } ?>
<?php
if
(
$currentPage
>= 2) { ?>
<li
class
=
"page-item"
><a
class
=
"page-link"
href=
"feedbacklist.php?page=<?php echo $previousPage ?>"
><?php
echo
$previousPage
?></a></li>
<?php } ?>
<li
class
=
"page-item active"
><a
class
=
"page-link"
href=
"feedbacklist.php?page=<?php echo $currentPage ?>"
><?php
echo
$currentPage
?></a></li>
<?php
if
(
$currentPage
!=
$lastPage
) { ?>
<li
class
=
"page-item"
><a
class
=
"page-link"
href=
"feedbacklist.php?page=<?php echo $nextPage ?>"
><?php
echo
$nextPage
?></a></li>
<li
class
=
"page-item"
>
<a
class
=
"page-link"
href=
"feedbacklist.php?page=<?php echo $lastPage ?>"
aria-label=
"Next"
>
<span aria-hidden=
"true"
>Last</span>
</a>
</li>
<?php } ?>
</ul>
</nav>
Reply
Answers (
2
)
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