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p c
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27.2k
Opening .exe file using OpenFileDialog() in C#
Jan 31 2008 8:58 AM
Hi, i want open an .exe file using OpenFileDialog() in C#
The code i ve used is -
Stream strm;
StreamReader reader;
try
{
strm = OpenFileDialog1.OpenFile();
reader = new StreamReader(strm);
}
catch (Exception err)
{
string Message = err.Message + "\n\nCannot open "
+ OpenFileDialog1.FileName;
MessageBox.Show(Message, "Open error",
MessageBoxButtons.OK,
MessageBoxIcon.Error);
return;
}
reader.ReadToEnd();
reader.Close();
strm.Close();
But, I m getting an error..
Can anybody tell me the cause....
Thanx in advance
Reply
Answers (
5
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