Opening a .MSG file using Process.Start()

Zen Liu Zhanhong

ProcessStartInfo startInfo = new ProcessStartInfo(); Process first = new Process(); startInfo.FileName = "OUTLOOK"; startInfo.Arguments = "http:\\blabla.com\EMAIL.msg"; startInfo.CreateNoWindow = true; first.StartInfo = startInfo; first.Start();i used Process.Start to start up Outlook and open a .Msg file. how can i reuse the same process to open another .msg file without opening multiple windows of outlook?
i have tried something like
Process[] outlook = Process.GetProcessesByName("OUTLOOK"); Process existing = outlook[0]; startInfo.FileName = "outlook"; startInfo.Arguments = "http:\\blabla.com\2ndEMAIL.msg"; startInfo.CreateNoWindow = true; existing.StartInfo = startInfo; existing.Start(); to reuse the same process but i'm still opening multiple windows of outlook instead of just the .MSG file

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Zen Liu Zhanhong11y ago
i'm not trying to close the previous .msg file that i have opened. the issue is that whenever i try opening another .msg file, a new outlook window appear
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Vulpes11y ago
I don't think you can re-use the existing process in this way.

I'd suggest instead that you check first whether there's an existing instance of outlook open and, if there is, close or kill it. You can then open a new instance with the appropriate .msg file:

Process[] outlook = Process.GetProcessesByName("OUTLOOK");
if(outlook.Length > 0)
{
for(int i = outlook.Length - 1; i >= 0; i--)
{
outlook[i].CloseMainWindow(); // or outlook[i].Kill();
outlook[i].WaitForExit();
outlook[i].Dispose();
}
}

outlook = null;

ProcessStartInfo startInfo = new ProcessStartInfo();
Process first = new Process();
startInfo.FileName = "OUTLOOK";
startInfo.Arguments = @"http:\\blabla.com\EMAIL.msg";
startInfo.CreateNoWindow = true;
first.StartInfo = startInfo;
first.Start();

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