Notepad in C# (txt file)

Manoj Maharana

public static void ShowMessage(DataTable message = null, string title = null)

{

Process notepad = Process.Start(new ProcessStartInfo("notepad.exe"));

// Process notepad = System.Diagnostics.Process.Start(new ProcessStartInfo("notepad.exe", "txt_notes.Text"));

// Process notepad = System.Diagnostics.Process.Start(new ProcessStartInfo("notepad.exe", Environment.GetEnvironmentVariable("windir")));

// Process notepad = System.Diagnostics.Process.Start(new ProcessStartInfo("notepad.exe", "txt_notes.Text"));

//Process notepad = Process.Start(new ProcessStartInfo(@"c:\myfile.txt"));

notepad.WaitForInputIdle();

if (!string.IsNullOrEmpty(title))

SetWindowText(notepad.MainWindowHandle, title);

if (notepad != null)

{

if (message.Rows.Count > 0)

{

StringBuilder sb = new StringBuilder();

sb.Append("Notes : ");

sb.Append(message.Rows[0]["Notes"].ToString());

sb.Append(Environment.NewLine);

sb.Append("Title : ");

sb.Append(message.Rows[0]["Title"].ToString());

Literal lt = new Literal();

lt.Text = sb.ToString();

IntPtr child = FindWindowEx(notepad.MainWindowHandle, new IntPtr(0), "Edit", null);

SendMessage(child, 0x000C, 0, lt.Text);

}

The problem is that it is not working on server...

i want to show text file in notepad.

error comes

Server Error in '/' Application.

Access is denied

13 Replies

Know the answer? Post it — somebody with the same question will find it here.

Manas Mohapatra10y ago
Please go through below links:
https://social.msdn.microsoft.com/Forums/en-US/f2e450cc-4fde-484c-8a1c-e86056544791/solved-c-access-is-denied-issue?forum=csharplanguage
http://stackoverflow.com/questions/26017273/access-to-the-path-c-log-txt-is-denied-in-file-create
Manoj Maharana10y ago
Is there any otherway to handel this problem??
no the same problem..
Server Error in '/' Application.
Access is denied
Tapan Patel10y ago
take a look at my updated answer. See the highlighted part.
Manoj Maharana10y ago
ProcessStartInfopinfo = newProcessStartInfo("notepad.exe");
ProcessInformation.UseShellExecute = false;
Process notepad = Process.Start(ProcessInformation);
notepad.WaitForInputIdle();

if (!string.IsNullOrEmpty(title))
SetWindowText(notepad.MainWindowHandle, title);
Error comes:
The name ProcessStartInfopinfo doesn't exist in the current context
Tapan Patel10y ago
Instead of
Process notepad=Process.Start(newProcessStartInfo("notepad.exe"));
try this.
ProcessStartInfo pinfo=newProcessStartInfo("notepad.exe");
pinfo.UseShellExecute=false;
Process notepad = Process.Start(pinfo);
Manoj Maharana10y ago
where should i write??
ProcessInformation does not exist in the current contex...
Tapan Patel10y ago
Hmm.
Try this.
Take out the processStartInfo object out just to set the properties on that.

And set property ProcessInformation.UseShellExecute = False;
And try running it again.

Manoj Maharana10y ago

sir is there anything missing in dll??

using System.Web.UI.WebControls;

using System.Data;

using System.Text;

using System.Runtime.InteropServices;

using System.Diagnostics;

using System.IO;

This is error:

Server Error in '/' Application.

Access is denied

Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code.

Exception Details: System.ComponentModel.Win32Exception: Access is denied

Source Error:

An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below.

Stack Trace:

[Win32Exception (0x80004005): Access is denied]    System.Diagnostics.Process.StartWithShellExecuteEx(ProcessStartInfo startInfo) +773    System.Diagnostics.Process.Start() +123    System.Diagnostics.Process.Start(ProcessStartInfo startInfo) +49    ksoftweb.Control.FTPAddEdit.ShowMessage(DataTable message, String title) +63    ksoftweb.Control.FTPAddEdit.btnexnotpade_Click(Object sender, EventArgs e) +907    System.Web.UI.WebControls.LinkButton.OnClick(EventArgs e) +116    System.Web.UI.WebControls.LinkButton.RaisePostBackEvent(String eventArgument) +101    System.Web.UI.WebControls.LinkButton.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) +10    System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) +13    System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) +9665050    System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +1724

Tapan Patel10y ago
That is something you already mentioned in your question but I think you are missing something on server.
Okay, Let me know the type of Exception you are getting. Debug the code and (make sure that your IDE is configured to break on all type of exception. If I am not wrong, you should get UnauthorizedAccessException.
Please let me know the type of Exception.
Manoj Maharana10y ago
When Click on Export to text button all the data need to come in a txt file and show in notepad
This is working fine in localhost but problem in server.
Here is the code :
protected void btnexnotpade_Click(object sender, EventArgs e)
{
DataTable dtRecords = new DataTable();
dtRecords.Columns.Add("Host", typeof(string));
..........................
object[] obj = { txt_host.Text, txt_userName...............};
dtRecords.Rows.Add(obj);
ShowMessage(dtRecords, txt_notes.Text);
}
Tapan Patel10y ago
As you mentioned that you are getting the error. So go to the folder where you are trying to Open/Edit/Write this notepad file (on whatever system - local or server) , try creating simple notepad file without an application, (simply by doing right click - Create new text file), If that is asking you for permission, then you need to address it.
Manoj Maharana10y ago
I am not getting..can you describe me proprely
How to do manually ..You just write down the code
Tapan Patel10y ago
Do you have an access to edit or save the file on the location where you app is running?

Try doing that manually, if that asks for the permission or doesn't allow you, you may need to make changes in your application to deal with permission issue.

Please marks it as answer if it resolves the issue.