TECHNOLOGIES
FORUMS
JOBS
BOOKS
EVENTS
INTERVIEWS
Live
MORE
LEARN
Training
CAREER
MEMBERS
VIDEOS
NEWS
BLOGS
Sign Up
Login
No unread comment.
View All Comments
No unread message.
View All Messages
No unread notification.
View All Notifications
Answers
Post
An Article
A Blog
A News
A Video
An EBook
An Interview Question
Ask Question
Forums
Monthly Leaders
Forum guidelines
Mark Tabor
587
2k
457.1k
MVc dynamic Menu using Partial View
May 12 2016 5:04 AM
I have made a simple Dynamic MVC menu application in which i have an entity model and i bind this entity model from database table {Menu table} , I have created a simple MVC application in which it automatically add home controller and i wrote the below c0de in home controller
private TestEntities testEntities = new TestEntities();
public ActionResult Index()
{
ViewBag.MenuLevel1 = this.testEntities.Menus.Where(menu=>menu.ParentId==null ).ToList();
return View();
}
Secondly I have Menu Folder Under Views and in this Menu folder i have index view and my index view is just look like that
@model Menu.Models.Menu
<ul>
@foreach (var menuLevel1 in ViewBag.MenuLevel1)
{
<li>@menuLevel1.Name
@if (menuLevel1.Child.Count > 0)
{
<ul>
@foreach (var menuLevel2 in menuLevel1.Child)
{
<li>
@menuLevel2.Name
</li>
}
</ul>
}
</li>
}
</ul>
Now i want to make this Menu item as partial view and want to call it from _LAyout.cshtml how to do that ? i have check lot of example non of them makes me happy :)
Reply
Answers (
2
)
Create thumbnail image from video file
Dynamic Menu using angularjs mvc