Method invoking

Question

 Sir,

 

I am not understanding the below code of method. pls explain. 

 

 

static void PrintNumber(int numberParam)

{

// Modifying the primitive-type parameter

numberParam = 5;

Console.WriteLine("in PrintNumber() method, after " +

"modification, numberParam is: {0}", numberParam);

}

 

Invocation of the method from Main():

 

static void Main()

{

int numberArg = 3;

// Copying the value 3 of the argument numberArg to the

// parameter numberParam

PrintNumber(numberArg);

Console.WriteLine("in the Main() method numberArg is: " +

numberArg);

}

 

 

The result from the above line is printed below:

in PrintNumber() method, after modification, numberParam is: 5

in the Main() method numberArg is: 3

 

1. Pls explain what is method declaration, invocation, argument in simple words.