Meaning of code and be Output of it !

In binary:

b1 is assigned 1010 1011 

b2 is assigned 1001 1001 ( = 153 decimal)

To understand the rest of it, note that all byte values are implicitly converted to ints before applying bit operators. Casting to byte then converts the result back to the byte type (low order 8 bits).

Note also that when you shift bits to the left or right if the number of places to shift exceeds 31, only the low order 5 bits is considered. This is equivalent to reducing the number of places modulo 32.

So, to begin with, this line:

temp = (byte)~b2; 

flips the bits of b2 and assigns the result to temp. So:

temp = 0110 0110 which is 0x66 hex or 102 decimal.

The decimal number (102) is then printed to the console followed by a space.

This next line:

temp = (byte)(b1 << b2); 

shifts the bits of b1 by (b2 modulo 32) (= 25 decimal) places to the left. As there are only 32 bits in b1 (after conversion to an int), this results in all 8 lower order bits of b1 being discarded and replaced with zeros. 

Consequently, the value of temp after this operation is 0 and this gets printed to the console followed by a space.

Finally, this line:

temp = (byte) (b2 >> 2); 

shifts the bits of b2 two places to the right resulting in:

temp = 0010 0110  which is 0x26 hex or 38 decimal.

The decimal number (38) is then printed to the console followed by a line terminator.

So we end up with this console output:

102 0 38