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Sousa Pambo

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insert images into sql

Mar 3 2015 6:31 PM
I have a bug inserting two images into sql what is wrong with this
 
public void LancaResponsavel_1(UIL.frmCadAluno frmAl)
{
System.Text.StringBuilder sqlBuilder = new System.Text.StringBuilder();
sqlBuilder.Append("INSERT INTO tbResponsavel");
sqlBuilder.Append("(apelidoR, idAlunoR, nomeR, contactoR, sexoR, dtNascR, parentescoR, bairroR, Av_ruaR, qrteraoR, fotoR, CasaR, apelidoR2, nomeR2, contactoR2, sexoR2, dtNascR2, parentescoR2, bairroR2, Av_ruaR2, qrteraoR2,fotoR2 , fotoRCasaR2)");
sqlBuilder.Append(" VALUES ('");
sqlBuilder.Append(frmAl.tbApelidResp1.Text + "','"); //1
sqlBuilder.Append(frmAl.tbRefCadastro.Text + "','"); //2
sqlBuilder.Append(frmAl.tbNomResp1.Text + "','"); //3
sqlBuilder.Append(frmAl.tbcntctoR1.Text + "','"); //4
sqlBuilder.Append(frmAl.sexoR + "','"); //5
sqlBuilder.Append(frmAl.dtNascResp1.Text + "','"); //6
sqlBuilder.Append(frmAl.cbParentescResp1.Text + "','"); //7
sqlBuilder.Append(frmAl.tbBairroResp1.Text + "','"); //8
sqlBuilder.Append(frmAl.tbAvenResp1.Text + "','"); //9
sqlBuilder.Append(frmAl.tbQrtResp1.Text + "',"); //10
sqlBuilder.Append("@PicResp1,'"); //11
sqlBuilder.Append(frmAl.tbCasaResp1.Text + "','"); //12
sqlBuilder.Append(frmAl.tbapelidResp2.Text + "','"); //1
sqlBuilder.Append(frmAl.tbNomResp2.Text + "','"); //2
sqlBuilder.Append(frmAl.tbCntactoR2.Text + "','"); //3
sqlBuilder.Append(frmAl.sexoR2 + "','"); //4
sqlBuilder.Append(frmAl.dtNascResp2.Text + "','"); //5
sqlBuilder.Append(frmAl.cbParentescResp2.Text + "','"); //6
sqlBuilder.Append(frmAl.tbBairroResp2.Text + "','"); //7
sqlBuilder.Append(frmAl.tbAvenResp2.Text + "','"); //8
sqlBuilder.Append(frmAl.tbQrtResp2.Text + "','"); //9
sqlBuilder.Append("@PicResp2,'"); //10
sqlBuilder.Append(frmAl.tbCasaResp2.Text + "')"); //11
using (SqlConnection myconn = new SqlConnection(con.stringConexaoRH()))
try
{
myconn.Open();
using (SqlCommand cm = new SqlCommand(sqlBuilder.ToString(), myconn))
{
MemoryStream ms = new MemoryStream();
frmAl.pbFotoResp1.Image.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp);
cm.Parameters.Add("@PicResp1", SqlDbType.Image).Value = ms.ToArray();
frmAl.pbFotoResp2.Image.Save(ms, System.Drawing.Imaging.ImageFormat.Bmp);
cm.Parameters.Add("@PicResp2", SqlDbType.Image).Value = ms.ToArray();
cm.ExecuteNonQuery();
}
}
catch (Exception ex)
{
MessageBox.Show("" + ex);
}
}
 

Answers (3)