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I want to know that how this equation is working.

I want to know that how this equation is working.

Saurabh Sarkar

10y2.7kVisual Basic .NET

class Program

{

static void Main(string[] args)

{

int x = 4, b = 2;

x -= b /= x * b;

Console.WriteLine(x + " " + b);

Console.ReadLine();

}

}

4 Replies

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Sachin Singh4y ago
You are confused because multiple assignment operators is being used in a single line. This is normal in c#.
means a=b=c=d=4; is just normal.

Remember assignment operator works from right to left.
int x = 4, b = 2;
x -= b /= x * b;
so the compiler will first execute below part
b /= x * b;
b=b/(x*b) = 1/x; (1/4 that gives 0)
second
x= x- (b/(x*b))
that gives x=(4-0)=4
finally, x=4, b=0;
Muhammad Imran Ansari4y ago
These are called shorthand
a -= b is equivalent to a = a - b
a *= b is equivalent to a = a * b
a /= b is equivalent to a = a / b
Now Equation is:
int x = 4, b = 2;
x -= b /= x * b;
is same as
b = b/x * b;
x = x - b;
You can read more regarding operators:
https://docs.microsoft.com/en-us/previous-versions/visualstudio/visual-studio-2012/6a71f45d(v=vs.110)?redirectedfrom=MSDN
Himanshu Mishra4y ago
I can make simple ,
convert equation in two parts
b= b / x * b ex= 2/4*2= 2/8=0 because b is interger
x= x-b ex- 4-0= 0
output is 4,0
Nitin Sontakke10y ago
Does it makes sense if I put brackets in order of expression evaluation!
x -= (b /= (x * b));
Remember that the values are assigned from right to left.
So, in C# you will not see many developers write as follows, but it perfectly legal and efficient:
String a, String b, String c, String d, String e;
a = b = c = c = d = e = String.Empty;
The above will initialize all 5 variables to String.Empty.