I want to know that how this equation is working.

Question

class Program { static void Main(string[] args) { int x = 4, b = 2; x -= b /= x * b; Console.WriteLine(x + " " + b); Console.ReadLine(); } }

Sachin Singh · Answer

You are confused because multiple assignment operators is being used in a single line. This is normal in c#. means a=b=c=d=4; is just normal. Remember assignment operator works from right to left. int x = 4, b = 2; x -= b /= x * b; so the compiler will first execute below part b /= x * b; b=b/(x*b) = 1/x; (1/4 that gives 0) second x= x- (b/(x*b)) that gives x=(4-0)=4 finally, x=4, b=0;

Muhammad Imran Ansari · Answer

These are called shorthand a -= b is equivalent to a = a - b a *= b is equivalent to a = a * b a /= b is equivalent to a = a / b Now Equation is: int x = 4, b = 2; x -= b /= x * b; is same as b = b/x * b; x = x - b; You can read more regarding operators: https://docs.microsoft.com/en-us/previous-versions/visualstudio/visual-studio-2012/6a71f45d(v=vs.110)?redirectedfrom=MSDN

Himanshu Mishra · Answer

I can make simple , convert equation in two parts b= b / x * b ex= 2/4*2= 2/8=0 because b is interger x= x-b ex- 4-0= 0 output is 4,0

Nitin Sontakke · Answer

Does it makes sense if I put brackets in order of expression evaluation! x -= (b /= (x * b)); Remember that the values are assigned from right to left. So, in C# you will not see many developers write as follows, but it perfectly legal and efficient: String a, String b, String c, String d, String e; a = b = c = c = d = e = String.Empty; The above will initialize all 5 variables to String.Empty.

I want to know that how this equation is working.

Answers (4)