How to multiply N number for each number in a Linked list?

Carlos Robles Calderon

Well, i'm a total noob in this of codding and programming so sorry if i say something stupid or without logic at all... Wel the problem is that i have a algorithm or a program that i have to do (University Homework), and i dont get how to do it.. This is what i have:

#include
#include
#include
#include

using namespace std;

int main(int argc, char *argv[]) {
list lalista;
double num, suma=0;

cout << "A Simple calc:" << endl;

do {
cout << "Insert a numbrer, or 0 to exit: ";
cin >> num;
if (num !=0) lalista.push_back(num);
}
while (num !=0);

cout << "-----------" << endl;

while( !lalista.empty() )
{
num = lalista.front();
cout << setw(10) << num << endl;
suma += num;
lalista.pop_front();
}
cout << "----------" << endl;

cout << setw(10) << suma << endl;

system ("PAUSE");

return EXIT_SUCCESS;
}

in this one is adding the whole thing, and i dont get how to put it to multiply each of the number stored in the linked list, could help me? Thanks (i'm working in c++ sorry, if i disrupt you).

3 Replies

Know the answer? Post it — somebody with the same question will find it here.

Vulpes11y ago
Accepted answer
Try this:

#include
#include
#include
#include

using namespace std;

int main(int argc, char *argv[]) {
list lalista;
double num, suma=0, N;

cout << "A Simple calc:" << endl;

do {
cout << "Insert a number, or 0 to exit: ";
cin >> num;
if (num !=0) lalista.push_back(num);
}
while (num !=0);

cout << endl << "What do you want to multiply them by: ";
cin >> N;
cout << "-----------" << endl;

while( !lalista.empty() )
{
num = N * lalista.front();
cout << setw(10) << num <
suma += num;
lalista.pop_front();
}
cout << "-----------" << endl;

cout << setw(10) << suma << endl;

system ("PAUSE");

return EXIT_SUCCESS;
}
Vulpes11y ago
Sure, all I did is the following:

1. I've added a new variable, N, to hold the number which the numbers in the linked list are to be multiplied by.

2. I've then asked the user for the value of N.

3. Finally, the first number in the linked list has been multiplied by N and the result stored in the existing variable num:

num = N * lalista.front();

The rest of the code then works as it did before except that it displays and adds the numbers after multiplication by N rather than just the numbers themselves.
Carlos Robles Calderon11y ago
BRO!!!!! (@vulpes) Your're fcking awesome, thank you.... could you just explain me what you did in your words, i think i got what you did but if no troubling you, could you? But anyways, THANKS, THANKS, THANK YOU, REALLY THANKFUL TO YOU!