how to identify Sever and client in a given code

#include
int copy (char *srcm char *dst) { /* procedure to copy file using the server */
struct message m1 ; /* message buffer */
long position ; /* current file position */
long client =110; /* client’s address */
initialize () ; /* prepare for execution */
position = 0 ;
do { /* Get a block of data from the source file */
m1.opcode = READ ; /* operation is read */
m1.offset = position ; /* current position in the file */
m1.count = BUF_SIZE ; /* how many bytes to read */
strcpy(&m1.name, src) ; /* copy name of file to be read to message */
send (FILE_SERVER, &m1) ; /* send the message to the file server */

receive (client, &m1) ; /* block waiting for the reply */

#include
void main(int argc, char **argv) {
struct message m1, m2 ; /* incoming and outgoing messages */
int r ; /* result code */
while (1) { /* server runs forever */
receive (FILE_SERVER, &m1) ; /* block waiting for a request */
switch (m1.opcode) { /* dispatch on type of request */
case CREATE : r = do_create(&m1, &m2) ; break ;
case READ : r = do_read(&m1, &m2) ; break ;
case WRITE : r = do_write (&m1, &m2) ; break ;
case DELETE : r = do_delete (&m1, &m2) ; break ;
default : r = E_BAD_OPCODE ;
}
m2.result = r ; /* return result to client */
send (m1.source, &m2) ; /* send reply */
}};

1 Reply

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Dharmraj Thakur9y ago
Accepted answer
Client always request first and server always listening or waiting for any request...
So here in your code first code is client code and second is server code because of this can be make sense...
while (1) { /* server runs forever */
it will always listen something received from client
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