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Nymhar Quines
NA
136
110.6k
How to get the query in LINQ of a hierarchical database
May 28 2013 2:32 AM
Sample data from table: Table Name - SUPPLIERS and Entity Name - dbData
RECORD_NO ID_NO FIRST_BRANCH SECOND_BRANCH POSITION
----------------------------------------------------------------
1 05100242 05100243 05100244 L
2 05200443 05100245 05100247 L
3 05100244 05100248 R
4 05100245 05100249 L
5 05100247 05100250 R
6 05100248 L
7 05100249 L
8 05100250 L
HIERARCHY ILLUSTRATION
For example in a pyramid organizational chart, how are you going to get the count of A,B and C?
A = 05100242
B = 05100243
C = 05100244
TO GET THE RESULT OF 05100242 I used
LEFT ACCOUNT
var data = dbData.SUPPLIERS.where(x=>x.ID_NO == 05100243);
LEFT
string left = data.FIRST_BRANCH;
var leftbranch = dbData.where(x=>x.ID_NO == left);
RIGHT
string right = data.SECOND_BRANCH;
var leftbranch = dbData.where(x=>x.ID_NO == right);
RIGHT ACCOUNT
var data2 = dbData.SUPPLIERS.where(x=>x.ID_NO == 05100244);
LEFT
string left2 = data2.FIRST_BRANCH;
var leftbranch = dbData.where(x=>x.ID_NO == left2);
RIGHT
string right2 = data2.SECOND_BRANCH;
var leftbranch = dbData.where(x=>x.ID_NO == right2);
The problem is for every ID_NO, you need to get the
LEFT AND RIGHT
BRANCH
and
the result is you need to get
again
the
LEFT AND RIGHT
. YOU NEED TO REPEAT THIS DEPENDING ON HOW MANY RECORDS AVAILABLE.
THE QUESTION IS WHAT IF THERE ARE
MILLIONS
ON RECORDS?
AND RECORDS IS
INCREASING
BECAUSE EVERYDAY SUPPLIERS/DEALERS ARE CONTINUE GROWING.
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