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siva nathan
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How to get column value like this in sql?
Mar 22 2017 6:34 AM
intime
outtime
21-03-2017 09:01:22
21:03:2017 20:00:00
My expected output like this
intime
OTIN
OTOUT
outtime
21-03-2017 09:01:22
21-03-2017 18:01:22
21-03-2017 18:01:22
21-03-2017 20:00:00
if outtime is greater then 08pm (20:00) means OTIN time assigned as 06 pm(10:00)
same Time as OTOUT finally outtime as Outtime
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Json.NET deserializing custom object returns null
Explain Test Passed->Test Explorer (using NUnit)