how to create a thumbnail from video in window form c#

Question

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;

using System.Diagnostics;

using System.IO;

namespace Sample_Thumbnail

{

public partial class Form : System.Windows.Forms.Form

{

private Image imgThumb;

public Form()

{

InitializeComponent();

}

public static string generateThumb(string file)

{

string thumb = "";

try

{

FileInfo fi = new FileInfo(file);

string filename = Path.GetFileNameWithoutExtension(fi.Name);

Random random = new Random();

int rand = random.Next(1, 9999999);

string newfilename = "C:\\Users\\user\\Desktop\\Preethi\\Sample_Thumbnail\\Sample_Thumbnail\\bin\\Debug\\" + filename + "___(" + rand.ToString() + ").jpg";

var processInfo = new ProcessStartInfo();

processInfo.FileName = @"C:\Users\user\Desktop\Preethi\Sample_Thumbnail\Sample_Thumbnail\bin\Debug\ffmpeg.exe";

processInfo.Arguments = string.Format("-ss {0} -i {1} -f image2 -vframes 1 -y {2}", 5, "\"" + file + "\"", "\"" + newfilename + "\"");

processInfo.CreateNoWindow = true;

processInfo.UseShellExecute = false;

using (var process = new Process())

{

process.StartInfo = processInfo;

process.Start();

process.WaitForExit();

thumb = newfilename;

}

}

catch (Exception ex)

{

string error = ex.Message;

}

return thumb;

}

private void Generate_Click(object sender, EventArgs e)

{

string thumb = "";

Image image = null;

// Check if textbox has a value

if (txtFileNm.Text != String.Empty)

thumb = generateThumb(txtFileNm.Text);

image = Image.FromFile(thumb.ToString());

if (image != null)

{

imgThumb = image.GetThumbnailImage(100, 100, null, new IntPtr());

// Refresh();

}

pictureBox1.Image = imgThumb;

}

private void Form1_Paint(object sender, PaintEventArgs e)

{

if (imgThumb != null)

e.Graphics.DrawImage(imgThumb, 30, 20, imgThumb.Width, imgThumb.Height);

}

private void button1_Click(object sender, EventArgs e)

{

if (openFileDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)

{

txtFileNm.Text = openFileDialog1.FileName;

}

}

}

}