How to convert code from C#(2005) to VB.NET(2000)

Question

how to convert c# code version 2.0(2005) to vb.net 1.0(2000)
i have tried the following sites to convert but that r convert from 2005 to 2005


<a href="http://www.developerfusion.com"></a>
<a href="http://www.tangiblesoftwaresolutions.com"></a>
post solution for this


or otherwise say solution for this in VS 2000 gridview is not available, so i used datagrid control in that. In that datagrid control Rows property is not available.
    protected void btnadddata_Click(object sender, EventArgs e)
    {
        SqlConnection con = new SqlConnection("Data Source=.;Initial Catalog=TNVKP_8;Integrated Security=True");
        for (int i = 0; i < GridView2.Rows.Count; i++)
        {
            //GridViewRow row = GridView1.Rows[i];
            //CheckBox chkbox = (CheckBox)row.FindControl("chkbox1");
            CheckBox chkbox = (CheckBox)GridView2.Rows[i].FindControl("chkbox1");
            Label label1 = (Label)GridView2.Rows[i].FindControl("Label1");
            Label label2 = (Label)GridView2.Rows[i].FindControl("Label2");
            Label label3 = (Label)GridView2.Rows[i].FindControl("Label3");
            Label label4 = (Label)GridView2.Rows[i].FindControl("Label4");
            Label label5 = (Label)GridView2.Rows[i].FindControl("Label5");
            Label label6 = (Label)GridView2.Rows[i].FindControl("Label6");
            Label label7 = (Label)GridView2.Rows[i].FindControl("Label7");
            Label label8 = (Label)GridView2.Rows[i].FindControl("Label8");
            Label label9 = (Label)GridView2.Rows[i].FindControl("Label9");
            Label label10 = (Label)GridView2.Rows[i].FindControl("Label10");
            if (chkbox.Checked == true) //&& (row.Cells[11].Text=="Ok")
            {
                con.Open();
                string str;
                str = "insert into employee (empid,empname,empaddress,empcity,empstate,empzip,emplic,empstatus,empp,empi) values('" + label1.Text + "','" + label2.Text + "','" + label3.Text + "','" + label4.Text + "','" + label5.Text + "','" + label6.Text + "','" + label7.Text + "','" + label8.Text + "','" + label9.Text + "','" + label10.Text + "')";
                SqlCommand com = new SqlCommand(str, con);
                com.ExecuteNonQuery();
                con.Close();
            }
            Label1.Text = "Records inserted";
        }
    }