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Gustavo
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How Do I: Creata a temp/work DataGridView?
Jun 7 2010 8:13 PM
Hello:
I need to create/define a temp/work DataGridView in a Class so I can do some pre-work. I tried the following line, but it seems to not work. Can someone tell me if its right or what I am missing?
DataGridView
dataGridViewTemp =
new
DataGridView
();
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public enum {0,1,8,18} is identifier excpected error??
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