Generate End IP address based on Start IP address & no. of S

Sanket Jain

I have 3 labels,3 textboxes &1 button control in my form.
2 input textbox & 1 output textbox
I have to generate end ip address depend on No. of static ip & start ip address
e.g
No of static ip=5
Start ip =192.168.10.10
then generate output as

end ip = 192.168.10.14

my aspx code is as following
********************************************************************************************

	:
	:	ValidationExpression="\b(25[0-5]\|2[0-4][0-9]\|[01]?[0-9][0-9]?)\.(25[0-5]\|2[0-4][0-9]\|[01]?[0-9][0-9]?)\.(25[0-5]\|2[0-4][0-9]\|[01]?[0-9][0-9]?)\.(25[0-5]\|2[0-4][0-9]\|[01]?[0-9][0-9]?)\b" ID="RegularExpressionValidator6" runat="server" ErrorMessage="Invalid IP !" ControlToValidate="txtStartIP">
onclick="btnGenerateIP_Click" />
	:	ValidationExpression="\b(25[0-5]\|2[0-4][0-9]\|[01]?[0-9][0-9]?)\.(25[0-5]\|2[0-4][0-9]\|[01]?[0-9][0-9]?)\.(25[0-5]\|2[0-4][0-9]\|[01]?[0-9][0-9]?)\.(25[0-5]\|2[0-4][0-9]\|[01]?[0-9][0-9]?)\b" ID="RegularExpressionValidator1" runat="server" ErrorMessage="Invalid IP !" ControlToValidate="txtEnd_IP">

******************************************************************

so please help me in coding part because I just started Programming & new in programming

8 Replies

Know the answer? Post it — somebody with the same question will find it here.

Guest User12y ago
Accepted answer
string s = "192.168.1.250";
string[] oct=s.Split('.'); int j=3;
int to_increment = 350;
while (to_increment > 0)
{
oct[j] = oct[j]+to_increment;
if(Convert.ToInt16(oct[j]) > 255)
{
to_increment = to_increment-255;
}
j--;
}
0
Guest User12y ago
Got it, you need to store all relevant IP's. Therefore you need to modify your code, e.g.,

string s = "192.168.1.1";
string[] oct=s.Split('.'); int j=3;
int to_increment = 100; int i=1;
while (to_increment > i)
{
oct[j] = oct[j]+i;
i++;
string temp= oct.join(","); //convert it back into e.g., 192.168.1.2 then 192.168.1.3
string sql ="insert into table1 (IPaddress) values (" + temp + ")";
db.Execute (sql);

}
0
Sanket Jain12y ago
My problem is following:
Start ip=192.168.10.1
No. of Static Ip=5
End IP=192.168.10.5
I want to store all 5 ip's in database
i.e. 192.168.10.1 ,
192.168.10.2,
192.168.10.3,
192.168.10.4,
192.168.10.5
so i use between operator i.e between('192.168.10.1','192.168.10.5')
but in insert query we can't use between operator
so gives me hints for that
0
Guest User12y ago
Thanks for accepting my respones!

i got confused, why do you need BETWEEN sql operator to store data.

user INSERT to store. rite
0
Sanket Jain12y ago
Thanks for this
Now I want to store that IP's in oracle database
How to generate the middle ip's I can try between operator but it shows wrong output so gives me hints like previous
0
Sanket Jain12y ago
Give me some hints to start the logic
I'm taking 2 variables & in that variables stores static ip & start ip
I am not able to divide start ip in 4 parts so tell me how to divide this.
0
Guest User12y ago
Thanks Sanket for accepting this answer!

Looking forward for interaction future...
0
Guest User12y ago
Why are you using RegexExpressionValidator for txtEnd_IP you can show it in Label itself, as it's an output.

For this requirement you need to right algorithm which will read via octect. IP adderss is divided in range from 0-255 in each octet. Suppose user enters in text box find
Example1
192.168.1.250 and static IPs: 10, so the output should be
192.168.2.5 -> txtEnd_ip

If you agree to this, please mark this "Acccepted" answer and then we shall proceed in writing logic to solve Example1
+1