Duplicate Entry Inserted While inserting DataTable

Question

Can anybody guide me, i'm inserting DataTable in database, using type table, at the same time i'm returning the 2 fields. The issue i'm suffering with is if there are 7 entries in DataTable to be inserted, then 14 entries will be inserted.

 

I'm i doing it wrong? what could be the right way to do this... Return is perfectly working... issue is just inserting double the num of rows in dt to be inserted

ALTER PROCEDURE [dbo].[proc_InsertStore_Recvry]
(@dt_Recovery Recovery_Store READONLY)
AS
Declare @RecoveryIDs as Table (IDs int, ClientIds int)
declare @StoreID int
declare @ClientID int
declare @Arrears decimal(18, 2)
declare @NetDues decimal(18, 2)
declare @Received decimal(18, 2)
Declare @RecoveryRecID int
begin
select * into #tempTable from @dt_Recovery
declare @Count int
set @Count= (select COUNT(*) from #tempTable)
while(@Count > 0)
begin
set @Count = @Count-1
set @ClientID = (Select top 1 ClientID from #tempTable)
set @StoredID = (Select top 1 StoredID from #tempTable where ClientID=@ClientID)
set @Arrears = (Select top 1 Arrears from #tempTable where ClientID=@ClientID)
set @NetDues = (Select top 1 NDues from #tempTable where ClientID=@ClientID)
set @Received = (Select top 1 Received from #tempTable where ClientID=@ClientID)
Insert into tblRecovery (StoreID, ClientID, Arrears, NetDues, Received)
values (@StoreID,@ClientID,@Arrears,@NetDues,@Received)
select @RecoveryID = Scope_Identity()
insert into @RecoveryIDs (IDs,ClientIds) values (@RecoveryID, @ClientID )
delete from #tempTable where ClientID=@ClientID
end
Select * from @RecoveryIDs