double image insert mysql

Question

I use WPF and C# in this project.
There is only an Insert button and a datagrid.
First I choose an image from datagrid,
then I press Insert button.
In my case when I press insert once, two images are inserted to my DB at the same time.
Where is the problem in my code?:

<Window x:Class="PupilReg.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="Image Insert" Height="674" Width="1009" WindowStartupLocation="CenterScreen" FontSize="15" FontWeight="Bold" ResizeMode="CanResizeWithGrip">
<Grid Margin="0,10,-8,-50">
<DataGrid Name="dataGrid1" Height="565" Width="435" Margin="474,53,100,65">
<DataGrid.ItemBindingGroup>
<BindingGroup/>
</DataGrid.ItemBindingGroup>
<DataGrid.Columns>
<DataGridTextColumn Header="Image_ID" Binding="{Binding Path=Image_ID}" Width="80"/>
<DataGridTemplateColumn Header="Image_BLOB" Width="200" IsReadOnly="True">
<DataGridTemplateColumn.CellTemplate>
<DataTemplate>
<Image Source="{Binding Path=Image_BLOB}" Width="160" Height="160" />
</DataTemplate>
</DataGridTemplateColumn.CellTemplate>
</DataGridTemplateColumn>
</DataGrid.Columns>
</DataGrid>
<Button x:Name="btnInsert" Content="Insert" HorizontalAlignment="Left" Margin="93,117,0,0" VerticalAlignment="Top" Width="75" Click="btnInsert_Click"/>
</Grid>
</Window>

using MySql.Data.MySqlClient;
using System;
using System.Data;
using System.Windows;

namespace PupilReg
{
public partial class MainWindow : Window
{
string constr = "Data Source=localhost;port=3306;Initial Catalog=test;User Id=root;password=2525";
public MainWindow()
{
InitializeComponent();
BindGrid1();
}
public void BindGrid1()
{
MySqlConnection con = new MySqlConnection(constr);
con.Open();
MySqlCommand cmd = new MySqlCommand("SELECT * FROM images", con);
MySqlDataAdapter da = new MySqlDataAdapter(cmd);
DataTable dt = new DataTable();
da.Fill(dt);
dataGrid1.ItemsSource = dt.DefaultView;
}
private void btnInsert_Click(object sender, RoutedEventArgs e)
{
DataRowView SelectedRowValue = (DataRowView)dataGrid1.SelectedValue;
byte[] ImageBytes = (byte[])SelectedRowValue.Row.ItemArray[1];
MySqlConnection con = new MySqlConnection(constr);
MySqlCommand cmd = new MySqlCommand("INSERT INTO images (Image_BLOB) VALUES (@ImageSource)", con);
cmd.Parameters.Add("@ImageSource", MySqlDbType.Blob, ImageBytes.Length).Value = ImageBytes;
con.Open();
int i = cmd.ExecuteNonQuery();
if (i > 0)
{
cmd.ExecuteNonQuery();
MessageBox.Show("Image Inserted");
}
con.Close();
BindGrid1();
}
}
}