DevExpress MVCGridView

Question

Need a help in DevExpress. I have a custom button inside a Gridview. What I want is to create a ViewModel object when a user clicks on it.

Please revert me with possible solutions/suggestions.

@{

var grid = Html.DevExpress().GridView(settings =>

{

.

.

. 

GridViewCommandColumnCustomButton editBtn1 = new GridViewCommandColumnCustomButton();

editBtn1.ID = "Button1";

editBtn1.Image.Url = "~/Images/icons/manage_scrap_enable.png";

editBtn1.Text = "Details";

editBtn1.Image.IsResourcePng = true;

editBtn1.Visibility = GridViewCustomButtonVisibility.AllDataRows;

 var ccAdd = new MVCxGridViewCommandColumn();

ccAdd.CustomButtons.Add(editBtn1); 

...

 

}

 

 

Now on click of editButton1 I want to pass rowdata {column cell values}  to a MVC Controller action method as a Model object.

 

If it is a normal hyperlink or a button; we can create object of Model class inside a DataItemTemplate; but this is a custom button.

 

Please refer : http://www.devexpress.com/Support/Center/Example/Details/E4058 for sample implementation with normal GridViewColumn