TECHNOLOGIES
FORUMS
JOBS
BOOKS
EVENTS
INTERVIEWS
Live
MORE
LEARN
Training
CAREER
MEMBERS
VIDEOS
NEWS
BLOGS
Sign Up
Login
No unread comment.
View All Comments
No unread message.
View All Messages
No unread notification.
View All Notifications
Answers
Post
An Article
A Blog
A News
A Video
An EBook
An Interview Question
Ask Question
Forums
Monthly Leaders
Forum guidelines
Atta Kumah
NA
167
12.3k
Developing an Employee ASP.NET MVC Base Application
Mar 31 2019 5:20 AM
I am Developing an Employee ASP.NET MVC Base Apllication, But the Problem is that I want to select a particular Employee Like the one Below without using the same page with the input form.
Name
Sulon
Address
Pibilla
City
EmpireLodge
Submit
Name Address City
Sulon Pibila EmpireLoge
Sulon Pibilla EmpireLoge
Sulon Pibilla EmpireLoge
I want it that if An employee Enter His Details in One form, then He get the details in Another form. Please I need Help. Any Answer is highly appreciated.
public ActionResult Add_Record()
{
return View();
}
[HttpPost]
public ActionResult Add_Record(FormCollection FmC)
{
string user = FmC["Name"];
Employee Emp = new Employee();
Emp.Name = FmC["Name"];
Emp.Address = FmC["Address"];
Emp.City = FmC["City"];
Emp.Pin_Code = FmC["Pin_Code"];
Emp.Designation = FmC["Designation"];
DAlayer.AddDetails(Emp);
var Data = USB.tbl_Employee.Where(x => x.Name == user);
return View(Data);
//return RedirectToAction("SRD");
}
View State
@model IEnumerable<AttaK.Models.tbl_Employee>
@{
Layout = null;
}
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width" />
<title>Add_Record</title>
<link href="~/Content/bootstrap.min.css" rel="stylesheet" />
</head>
<body>
<div>
<form method="post">
<div class="form-group">
<label class="col-sm-3 control-label no-padding-right">Name </label>
<div class="col-sm-9">
<input type="text" name="Name" class="col-xs-10" />
</div>
</div>
<div class="form-group">
<label class="col-sm-3 control-label no-padding-right">Address </label>
<div class="col-sm-9">
<input type="text" name="Address" class="col-xs-10" />
</div>
</div>
<div class="form-group">
<label class="col-sm-3 control-label no-padding-right">City</label>
<div class="col-sm-9">
<input type="text" name="City" class="col-xs-10" />
</div>
</div>
<div class="form-group">
<label class="col-sm-3 control-label no-padding-right">Pin_Code</label>
<div class="col-sm-9">
<input type="text" name="Pin_Code" class="col-xs-10" />
</div>
</div>
<div class="form-group">
<label class="col-sm-3 control-label no-padding-right">Designation </label>
<div class="col-sm-9">
<input type="text" name="Designation" class="col-xs-10" />
</div>
</div>
<div class="form-group">
<div class="col-sm-9">
<input type="submit" name="Submit" class="btn btn-primary" />
</div>
</div>
</form>
</div>
<table class="table">
<tr>
<th>
@Html.DisplayNameFor(model => model.Name)
</th>
<th>
@Html.DisplayNameFor(model => model.Address)
</th>
<th>
@Html.DisplayNameFor(model => model.City)
</th>
<th>
@Html.DisplayNameFor(model => model.Pin_Code)
</th>
<th>
@Html.DisplayNameFor(model => model.Designation)
</th>
<th></th>
</tr>
@foreach (var item in Model)
{
<tr>
<td>
@Html.DisplayFor(modelItem => item.Name)
</td>
<td>
@Html.DisplayFor(modelItem => item.Address)
</td>
<td>
@Html.DisplayFor(modelItem => item.City)
</td>
<td>
@Html.DisplayFor(modelItem => item.Pin_Code)
</td>
<td>
@Html.DisplayFor(modelItem => item.Designation)
</td>
</tr>
}
</table>
</body>
</html>
Reply
Answers (
1
)
Implicit conversion from data type nvarchar to varbinary is
High qulity pdf create