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sawass sawass
NA
36
23.6k
brodcast stream in two sound card.
Jun 11 2011 10:14 AM
I
'm
planting
a
big problem
for x
days.
Is
anybody
can
help me
please
.
How
I
can order
the
pc
with
c
#
to
read me
the sound
in
two
sound cards
at the same
time
.
I
try
with
this
:
private void Start()
{
PaGa.WaveFormatStream fmt = new PaGa.WaveFormatStream(44100, 16, 2);
m_Recorder = new PaGa.WaveInRecorder(-1, fmt, 16384, 3, new PaGa.BufferDoneEventHandler(DataArrived));
m_Player = new PaGa.WaveOutPlayer(device1, fmt, 16384, 3, new PaGa.BufferFillEventHandler(Filler));
m_Recorder2 = new PaGa.WaveInRecorder2(-1, fmt, 16384, 3, new PaGa.BufferDoneEventHandler(DataArrived));
m_Player2 = new PaGa.WaveOutPlayer2(device2, fmt, 16384, 3, new PaGa.BufferFillEventHandler(Filler));}
But
how I
can
improve it
to
make
it
m_Player = new PaGa.WaveOutPlayer(device1, fmt, 16384, 3, new PaGa.BufferFillEventHandler(Filler));
and
that
at the same
time
m_Player2 = new PaGa.WaveOutPlayer2(device2, fmt, 16384, 3, new PaGa.BufferFillEventHandler(Filler));
for output audio
device
in
the
device
number 1
and
Number 2
.
In
the
main
function
call
with
integers
.
I need
help
.
It's
very
important to
me and
I have
not
found a solution
.
I
managed
sound
out
in
one
specific sound
card
by calling
his
number in
the
function
princpal
for example
if I
want to
listen to
the sound
in
the
sound card
number 1
I
wrote to him
in
parameter1
with
the
same method
except
that
I
put
only
this
:
m_Recorder = new PaGa.WaveInRecorder(-1, fmt, 16384, 3, new PaGa.BufferDoneEventHandler(DataArrived))
m_Player = new PaGa.WaveOutPlayer(device1, fmt, 16384, 3, new PaGa.BufferFillEventHandler(Filler));
I hope
my
message
is
not
very
long but
to
better
explain.
Reply
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