Alphabet Pattern 'U' in Python

In this Blog I am printing pattern 'U' using Python.

Code:

str="";
for Row in range(0,7):
    for Col in range(0,7):
        if (((Col == 1 or Col == 5) and Row != 6) or (Row == 6 and Col > 1 and Col < 5)):
            str=str+"*"
        else:
            str=str+" "
    str=str+"\n"
print(str);

Output: